Question 381519
{{{log(4/3,((4/3)^(1-x)))=log(4/3,5^x)}}}
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{{{1-x=log(4/3,5^x)}}}
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{{{1-x=x*log(4/3,5)}}}
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{{{x*log(4/3,5)+x=1}}}
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{{{x*(log(4/3,5)+1)=1}}}
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{{{x=1/(log(4/3,5)+1)}}}
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{{{x=1/(log(10,(5))/log(10,(4/3))+1)}}}
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{{{highlight(x=log(10,(4/3))/(log(10,(5))+log(10,(4/3))))}}}
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or approximately, 
{{{x=0.15}}}