Question 381513
<pre><font size = 3 color = "indigo"><b>
Hi
4y=2(x+1)^2-1
 y = (1/2)(x+1)^2 - 1/4
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
 Pt(-1,-1/4) is the vertex
y-intercept, when x  = 0
y = (1/2)*1 - 1/4
y = (1/2) Pt(0,1/4) the y intercept
x-intercept, when y = 0
 0 = (1/2)(x+1)^2 - 1/4
 1/4 = (1/2)(x+1)^2 
  2/4 = x^2 + 2x + 1
   0 = x^2 + 2x + 1/2
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-2 +- sqrt(2))/(2) }}}
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(-1, -.25,0.2),
circle(0, .25,0.2),
graph( 300, 300, -6, 6, -6, 6,.5(x+1)^2 - .25
 ))}}}