Question 381495
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Hi
Solving for x
  {{{3^(x^2)*27=9^(2x)}}}
   {{{(3^4)^(x^2)= (3^2)^(2x)}}}
  {{{(a^p)^q = a^(p*q)}}}
  {{{3^(4*x^2)=3^(4x)}}}
     4x^2 = 4x
    4x^2 - 4x = 0
    4x(x - 1) = 0
      x = 0
     (x - 1) = 0
      x = 1
 CHECKING the Answers
   0 = 0
  3*27 = 81 = 9^2