Question 381365
let the integers be n,n+2,n+4
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8times the sum
8*(n+n+2+n+4)
8*(3n+6)
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23 times smallest = 23n
add 98
23n+98
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8(3n+6)=23n+98
24n+48=23n+98
-23n   -23n
24n-23n+48=23n-23n+98
n+48=98
-48   -48
n+48-48=98-48
n=50 
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the numbers are 50, 52,54
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m.ananth@hotmail.ca