Question 381318
There are multiple ordered pairs of quarters and dimes (q, d) that satisfy. We want the amount of money from the quarters to be an odd multiple of 25 (i.e. something ending in .25 or .75) so that the amount from the dimes is a multiple of 10. Therefore we have

25q = 375, 10d = 10 --> 15 quarters, 1 dime
25q = 325, 10d = 60 --> 13 quarters, 6 dimes

Repeating this algorithm, we obtain (q, d) = (15, 1), (13, 6), (11, 11), (9, 16), (7, 21), (5, 26), (3, 31), (1, 36).