Question 381298
(-4,-6) and (1,3)
slope m of the line passing through above points =
=y2-y1  / x2-x1
=((3-(-6))/((1-(-4))
=(9/5)
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slope of line parallel to this linewill be the same  = 9/5
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Find  the value of b
plug x,y, & b in y= mx +b
-6=9/5*-4 +b
-6+36/5 =b
(-30+36)/5 =b
b= 6/5
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equation of line parallel to the line will be 
y= 9/5 *x +6/5
Y = 1.8 X  + 1.20
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Line perpendicular will have slope of negative reciprocal=  -5/9

y= -5/9x +6/5
y=--0.55x+1.20
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{{{graph(300,300,-5,5,-5,5,(1.8x+1.20),(-0.55x+1.20))}}}
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m.ananth@hotmail.ca