Question 381153
{{{(x^3-36x)/(x(x^2-9))=(x(x^2-36))/(x(x^2-9))=(highlight(x)(x^2-36))/(highlight(x)(x^2-9))=(cross(x)(x^2-36))/(cross(x)(x^2-9))=(x^2-36)/(x^2-9)}}}



So {{{(x^3-36x)/(x(x^2-9))=(x^2-36)/(x^2-9)}}}




Note: since the terms {{{x^2-36=(x+6)(x-6)}}} and {{{x^2-9=(x+3)(x-3)}}} have nothing in common, this means that there's no need to factor them.



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