Question 381034
Use the discriminant to determine the number and type of solutions of the equations.Your answer should be one real root, two real roots or two complex roots. 
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Circle the discriminant value. 
x^2+8x-6=0
b^2-4ac = 8^2-4*1*-6 >0 so there are 2 real roots
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4x^2-4x+1=0
b^2-4ac = 4^2-4*4*1 = 0 so there are 2 equal real roots
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Solve
Use the quadratic formula. 
x^4-9x^2-112=0 
x^2/3-7x^1/3+10=0
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Cheers,
Stan H.