Question 380875
Use a substitution,
let {{{u=1/x}}} and {{{v=1/y}}}.
1.{{{u+v=0}}}
2.{{{2u+5v=-6}}}
From eq. 1,
{{{u=-v}}}
Substitute into eq. 2,
{{{-2v+5v=-6}}}
{{{3v=-6}}}
{{{v=-2}}}
{{{1/y=-2}}}
{{{highlight(y=-1/2)}}}
Then from eq. 1,
{{{u=-(-2)}}}
{{{u=2}}}
{{{1/x=2}}}
{{{highlight(x=1/2)}}}