<PRE><B>Question 380853</B>
3x+2y=6 
x-intercept (_,0)
Let y = 0, then 3x=6; so x = 2 giving you (2,0)
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y_intercept (0,_)
Let x = 0, then 2y = 6; so y = 3 giving you (0,3)
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Checkpoint (1,_)
Let x = 1, then 3+2y = 6; 2y = 3; y = 3/2 giving you (1,3/2)
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Plot those points and draw a line thru them.
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{{{graph(400,300,-10,10,-10,10,(-3/2)x +3)}}}
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cheers,
stan H.
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