Question 380682
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Hi,
solving
x^2+2x-4 = 0
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-2 +- sqrt( 20))/(2) }}}
{{{x = (-2 +- sqrt( 4*5))/(2) }}}
{{{x = (-2 +- 2*sqrt( 5))/(2) }}}
{{{x = -1 +- sqrt(5)}}}