Question 380649
The difference of two numbers are 40. Six times the smaller one minus the larger one is 5. Find the larger number. 
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Equations:
x-y = 40
6y-x = 5
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Rearrange:
x - y = 40
x -6y = -5
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Subtract the bottom eq from the top and solve for "y":
5y = 45
y = 9
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Substitute into x-y = 40 and solve for "x":
x - 9 = 40
x = 49
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Cheers,
Stan H.