Question 380608
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Hi,
Using the point-slope formula, {{{m =(y[2] - y[1])/(x[2] - x[1])}}}to determine slope of L1
Points are (-4,0) and (0,6)which are the x and y intercepts 
  m = 6-0  / 0-(-4) = 6/4 = 3/2  
the standard slope-intercept form for an equation of a line is: y = mx + b  
where m is the slope and b the y-intercept.  Equation of L1 is y = (3/2)x + 6
Line2 parellel to L1 also has slope of 3/2
 y = 3/2x + b   L2 is to pass thru Pt(0,0) so b = 0
Equation of L2 is y = (3/2)x
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(-4, 0,0.3),
circle(0, 6,0.3),
graph( 300, 300, -6, 6, -6, 6,1.5x, 1.5x+6))}}}