Question 380584
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Hi,
1) An even number is any integer divisible by 2. 
Let 2n +1  and 2k + 1 represent two odd numbers
 (2n + 1) + (2k + 1) = 2(n+k+1) 
Letting N = (n+k+1)
 2n + 1 + 2k + 1 = 2N  sum is an even number as the integer is divisible by 2
Resulting Number is a number divisible by 2, therefore even
2) Let 2n  and 2k represent two even numbers
  2n*2k = 4(nk) Resulting Number is divisible by 4