Question 380394
Pick a coordinate system centered at the middle of the arch.
{{{y(44)=0}}}
{{{y(-44)=0}}}
{{{y(0)=88}}}
You can use the vertex form,
{{{y=-a(x-0)^2+88}}}
Use the boundary values to determine {{{a}}}.
{{{0=-a(44-0)^2+88}}}
{{{a(44)^2=88}}}
{{{a=88/(44)*2}}}
{{{a=1/22}}}
.
.
{{{highlight(y=-(1/22)x^2+88)}}}