Question 380466
The sum of the digits of a two digit number is 8. The value of the number is 2 less than 11 times the tens digit.Find the number. 
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Let the original number be 10t+u
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Equations:
t + u = 8
10t+u = 11t-2
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Simplify the 2nd equation:
t=u+2
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Substitute into the 1st equation and for for "u":
u+2 + u = 8
2u = 6
u = 3
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Since t=u+2, t = 5
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Original Number: 53
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Cheers,
Stan H.