Question 380408
Factor:
{{{2x^3+16}}} First, factor a 2.
{{{2(x^3+8)}}} Now notice that you have the sum of two cubes in the parentheses.
{{{2((x)^3+(2)^3)}}}
The sum of two cubes can be factored thus:
{{{A^3+B^3 = (A+B)(A^2-AB+B^2)}}} so in this problem, A = x and B = 2.
{{{highlight(2((x)^3+(2)^3) = 2(X+2)(x^2-2x+4))}}}