Question 41836
Let the side of its square base be 'a' ft.
Then the height is (3a + 68) ft.
The sum of these dimensions = (3a + 68) + a = (4a + 68).
But, given this sum is 1380 ft.
So, (4a + 68) = 1380
or 4a = 1312
or a = 1312/4 = 328
So the height of the Eiffel Tower is (3x328 + 68) = 1052 ft.