Question 380306
  <pre><font size = 3 color = "indigo"><b>
Hi,
Note:the standard slope-intercept form for an equation of a line is: y = mx + b  
where m is the slope and b the y-intercept.  
Line perpendicular to line y = 2/5x - 8, has slope = -(5/2) 
Equation of this line:
y = -(5/2)x + b  using ordered pair Pt(10,-4) to solve for b
-4 = -25 = b
21 = b  -25,25,-25,25,
y = -(5/2)x + 21
{{{drawing(300,300, -25,25,-25,25,
 grid(1),
circle(10, -4,0.9),
circle(0, 21,0.9),
graph( 300, 300, -25,25,-25,25,
-(5/2)x + 21 ))}}}