Question 41827
This problem is solved assuming simple interest per annum (S.I.P.A).


Let us suppose that Eva invested $x at 14% S.I.P.A.
Therefore she invested $(x+2000) at 15% S.I.P.A.


Interest on $x for 1 year at 14% S.I.P.A. = ${{{x*14/100}}}
Interest on $(x+2000) for 1 year at 15% S.I.P.A. = ${{{(x+2000)*15/100}}}
Therefore total interest in 1 year = ${{{x*14/100 + (x+2000)*15/100}}} = ${{{(29x+30000)/100}}}.
Given, her total yearly interest was $1460.00.


Then, {{{(29x+30000)/100 = 1460}}}
or 29x + 30000 = 146000
or 29x = 146000 - 30000 = 116000
or x = {{{116000/29}}} = 4000


Hence, Eva invested $4,000.00 at 14% and $6,000.00 at 15% simple interest per annum.