Question 380245
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Hi,
{{{a[n] = 4/(n+1)}}}
{{{a[1] = 4/(1+1)= 2}}}
{{{a[2] = 4/(2+1)= 4/3}}}
{{{a[3] = 4/(3+1)= 1}}}
{{{a[4] = 4/(4+1)= 4/5}}}
{{{a[100] = 4/(100+1)= 4/101}}}