Question 380225
 
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Hi,
f(x)=2x^2+4x+5  y=intercept Pt(0,5)
the vertex form of a parabola, {{{y=a(x-h)^2 +k}}} where(h,k) is the vertex
f(x)=2[(x^2 +2x} +5
f(x)=2[(x+ 1)^2 -1} +5
f(x)=2(x+ 1) -2 + 5
f(x)=2(x+ 1)+3
vertex Pt(-1,3), parabola opens upward (a=2 and is > than zero)
{{{x = (-b +- sqrt( b^2-4*a*c ))/(2*a) }}}
{{{x = (-4 +- sqrt(-24 ))/(4) }}}
 *[invoke quadratic "x", 2, 4, 5]