Question 380077
The length of the retangle is 6 meters less than twice the width. The perimter is 84 meters find the lenth and width.
 sol'n:
  let: l - the length of rectangle
       w - the width of rectangle
  l=2w-6 ----(1)
  P = 2l+2w
  2l+2w=84, divide 2 on both side to simplify
  l+w=42 -----(2)
 substitute (1) into (2).
  2w-6+w=42
  3w=42+6
  3w=48, divide both side by 3
   w=16
  from (1), substitute w to get the value of l
  l=2(16)-6
  l=26
and finally,
 l=26 m. -- answer
 w=16 m. -- answer