Question 41356
3x^2 = 11x + 4
3x^2 - 11x - 4 = 0
3x^2 - 12x + x - 4 = 0
3x(x - 4) + 1(x - 4) = 0
(3x + 1)(x - 4)=0
x = -1/3, 4


Using the formula
*[invoke quadratic "x", 3, -11, -4]