Question 380034
Find the (theoretical) probability of the given event, assuming that the coins are distinguishable and fair, and that what is observed are the faces uppermost.
Six coins are tossed; the result is at most one head.
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Binomial Problem:
n = 6 and p = 1/2
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P(0<= x <=1) = 6C0(1/2)^0(1/2)^6 + 6C1(1/2)^1(1/2)^5
= (1/2)^6 + 6(1/2)^6
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= 7(1/2)^6
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= 7/64
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Cheers,
Stan H.
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