Question 379554
Yes, an exponential function has the form, {{{y=ab^x}}}
Use both points.
{{{f(-3)=54}}} 
1.{{{54=ab^(-3)}}}
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{{{f(2)=2/9}}}
2.{{{2/9=ab^(2)}}}
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Divide eq. 2 by eq. 1 to eliminate {{{a}}}.
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{{{(2/9)/54=(ab^2)/(ab^(-3))}}}
{{{b^5=1/243}}}
{{{highlight(b=1/3)}}}
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Then use either equation to solve for {{{a}}}.
{{{2/9=a(1/3)^2}}}
{{{2/9=a/9}}}
{{{highlight(a=2)}}}
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{{{highlight_green(y=2(1/3)^x)}}}