Question 379605
{{{N^2+(N+1)^2=41}}}
{{{N^2+N^2+2N+1=41}}}
{{{2N^2+2N=40}}}
{{{N^2+N-20=0}}}
{{{(N+5)(N-4)=0}}}
Two solutions:
{{{N+5=0}}}
{{{N=-5}}}
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{{{N-4=0}}}
{{{N=4}}}
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Since they integers are positive, the integers are {{{4}}} and {{{5}}}.
The smaller number is {{{4}}}.