Question 379525
Let X be the random variable representing the earnings/loss at a single throw.  Then X = 1,3,5,-2,-4,-6.  We get the following discrete uniform probability mass function:
P(1) = P(2) =P(3) = P(-2) = P(-4) = P(-6) = 1/6.
The expected value is then {{{mu = (1+3+5)(1/6) + (-2-4-6)(1/6) = 9/6 - 12/6 = -1/2 = -0.50}}}.