Question 379392
Find the slope of the line.
{{{3x-4y=10}}}
{{{4y=3x-10}}}
{{{y=(3/4)x-5/2}}}
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Perpendicular lines have slopes that are negative reciprocals,
{{{m[1]*m[2]=-1}}}
{{{(3/4)*m[2]=-1}}}
{{{m[2]=-4/3}}}
Use the slope intercept form of a line,
{{{y=-(4/3)x+b}}}
Use the point ({{{-1}}},{{{2}}}) to solve for {{{b}}},
{{{2=4/3+b}}}
{{{b=6/3-4/3}}}
{{{b=2/3}}}
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{{{highlight(y=-(4/3)x+2/3)}}}
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{{{drawing(300,300,-5,5,-5,5,grid(1),circle(-1,2,0.2),graph(300,300,-5,5,-5,5,0,(3/4)x-5/2,-(4/3)x+2/3))}}}