Question 379139
  <pre><font size = 3 color = "indigo"><b>
Hi,
graphing
3x-2y=6
(3/2)x - 3 = y  
the standard slope-intercept form for an equation of a line y = mx + b  
where m is the slope and b the y-intercept. slope of this line is (3/2)
*[tex \large \ \ \ \ \ x \ \ \ \ \ y = 3/2x - 3 \ \ \ \ \ \ \ \ y]
*[tex \large \ \ \ \ -2 \ \ \ \ \ y = 3/2x - 3  \ \ \ \ \ -6]
*[tex \large \ \ \ \ \ 2 \ \ \ \ \ y = 3/2x - 3 \ \ \ \ \ \ \ 0]
*[tex \large \ \ \ \ \ 0 \ \ \ \ \ \ y = 3/2x - 3  \ \ \ \ \ \ -3]
Note as y increases/decreases by 3, x increases/decreases by 2
{{{drawing(300,300, -6, 6, -6, 6, grid(1),
circle(-2, -6,0.2),
circle(2, 0,0.2),
circle(0, -3,0.2),
graph( 300, 300, -6, 6, -6, 6,1.5x-3))}}}