Question 379027
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Hi,
{{{h(x)=14+x^2/4}}}
{{{h(2m)=14+(2m)^2/4 = 9m}}}
9m = 14 + 4m^2/4
m^2 -9m + 14 = 0
(m-7)(m-2) = 0 Note:SUM of the inner product(-7m) and the outer product(-2m)= -9m
(m-7)= 0
m = 7
(m-2) = 0
m = 2

f(x)=x-4/2
f(x)=30
30 = x - 2
32 = x