Question 378928
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Hi,
*[tex \large\ \ log_bx + log_by = log_b(xy) ]
*[tex \large\ \ log_bx - log_by = log_b(x/y) ]
expressing logx-log7-log8 in a single logarithm
     *[tex \LARGE\ \ log(x/7*8) \ = \ \ log(x/56)  ]