Question 378755
jim speed = 5 mph
let speed of wind be w mph
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against wind speed = 5-w
with wind speed = 5+w
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distance against wind = 6 miles
distance  with wind = 11 miles
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t=d/r
time against = time with
{{{6/(5-w)=11/(5+w)}}}
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cross multiply
6(5+w)=11(5-w)
30+6w=55-11w
6w+11w=55-30
17w=25
/17
w=25/17
w= 1.47 mph the speed of wind
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m.ananth@hotmail.ca