Question 378712
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(7,6\right)]. So this means that {{{x[1]=7}}} and {{{y[1]=6}}}.

Also, *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(10,-9\right)].  So this means that {{{x[2]=10}}} and {{{y[2]=-9}}}.



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-9-6)/(10-7)}}} Plug in {{{y[2]=-9}}}, {{{y[1]=6}}}, {{{x[2]=10}}}, and {{{x[1]=7}}}



{{{m=(-15)/(10-7)}}} Subtract {{{6}}} from {{{-9}}} to get {{{-15}}}



{{{m=(-15)/(3)}}} Subtract {{{7}}} from {{{10}}} to get {{{3}}}



{{{m=-5}}} Reduce



So the slope of the line that goes through the points *[Tex \LARGE \left(7,6\right)] and *[Tex \LARGE \left(10,-9\right)] is {{{m=-5}}}




If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim