Question 378709


<h4>x-intercept</h4>

To find the x-intercept, plug in {{{y=0}}} and solve for x



{{{x+5y=10}}} Start with the given equation.



{{{x+5(0)=10}}} Plug in {{{y=0}}}.



{{{x+0=10}}} Multiply {{{5}}} and 0 to get 0.



{{{x=10}}} Simplify.



So the x-intercept is *[Tex \LARGE \left(10,0\right)].



------------------------------------------



<h4>y-intercept</h4>

To find the y-intercept, plug in {{{x=0}}} and solve for y



{{{x+5y=10}}} Start with the given equation.



{{{0+5y=10}}} Plug in {{{x=0}}}.



{{{5y=10}}} Simplify.



{{{y=(10)/(5)}}} Divide both sides by {{{5}}} to isolate {{{y}}}.



{{{y=2}}} Reduce.



So the y-intercept is *[Tex \LARGE \left(0,2\right)].



Now let's plot the points *[Tex \LARGE \left(10,0\right)] and *[Tex \LARGE \left(0,2\right)] which are the x and y intercepts respectively.



{{{drawing(500, 500, -8,12,-10,10,
grid(0),
graph(500, 500, -8,12,-10,10,0)
circle(10,0,0.03),circle(10,0,0.05),circle(10,0,0.08),circle(10,0,0.10),circle(10,0,0.12),
circle(0,2,0.03),circle(0,2,0.05),circle(0,2,0.08),circle(0,2,0.10),circle(0,2,0.12)
)}}}



Now draw a straight line through the plotted points to graph {{{x+5y=10}}}.



{{{ drawing(500, 500, -8,12,-10,10,
grid(0),
graph(500, 500, -8,12,-10,10,(10-x)/(5)),
circle(10,0,0.03),circle(10,0,0.05),circle(10,0,0.08),circle(10,0,0.10),circle(10,0,0.12),
circle(0,2,0.03),circle(0,2,0.05),circle(0,2,0.08),circle(0,2,0.10),circle(0,2,0.12)
)}}} Graph of {{{x+5y=10}}}



If you need more help, email me at <a href="mailto:jim_thompson5910@hotmail.com?Subject=Algebra%20Help">jim_thompson5910@hotmail.com</a>


Also, feel free to check out my <a href="http://www.freewebs.com/jimthompson5910/home.html">tutoring website</a>


Jim