Question 378666
let them race for a distance of x meters
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Jenny gets a head start of 20 meters
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so her distance is x-20 meters
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Wendy walks x meters
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Jenny's apeed = 1.5 m/second
wendy speed = 2m/second
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If there has to be a tie ,they take same time.
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t= d/r
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Jenny's time = (x-20)/1.5
Wendy's time = x/2
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{{{x/2 = (x-20)/1.5}}}

cross multiply
1.5x=2(x-20)
1.5x=2x-40
-2x
1.5x-2x=-40
-0.5x=-40
/-0.5
x=-40/0.5
x=80 meters, the distance they have to race.
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m.ananth@hotmail.ca