<PRE><B>Question 378556</B>
If the product of two consecutive odd integers is increased by the third of the larger one the result is whose sum 190. Find the two integers
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1st: 2x-1
2nd: 2x+1

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Equation:
(2x-1)(2x+1)+(1/3)(2x+1) = 190
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4x^2-1 + (1/3)(2x+1) = 190
Multiply thru by 3 to get:
12x^2-3 + 2x+1 = 3*190
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12x^2+2x -2 = 570
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12x^2+2x - 572 = 0
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6x^2 + x - 286 = 0
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Note: I must have interpreted your post incorrectly.
Values of x would not produce integers.
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Cheers,
Stan H.</PRE>