Question 41621
{{{3x^3 - 2x^2}}} – 37x – 12
= {{{3x^3 + 9x^2 - 11x^2}}} – 33x - 4x – 12


[Look, here we have arranged the expression in such a way that factor (x + 3) can be taken common.]


= {{{3x^2(x + 3) - 11x(x + 3) - 4(x + 3)}}}
= {{{(x + 3)(3x^2 - 11x - 4)}}}
= {{{(x + 3)(3x^2 - 12x + x - 4)}}}
= {{{(x + 3)(3x(x - 4) + 1(x - 4))}}}
= {{{(x + 3)(3x + 1)(x - 4)}}}