Question 377973
Perpendicular lines’ slopes have the following relationship:
{{{m[1]*m[2]=-1}}}
{{{-3*m[2]=-1}}}
{{{m[2]=1/3}}}
Use the slope-intercept form,
{{{y=(1/3)x+b}}}
Use the point ({{{6}}},{{{-2}}}) to solve for {{{b}}}.
{{{-2=(1/3)(6)+b}}}
{{{b=-4}}}
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{{{highlight(y=(1/3)x-4)}}}
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{{{drawing(300,300,-8,8,-8,8,grid(1),circle(6,-2,0.3),graph(300,300,-8,8,-8,8,0,-3x+4,(1/3)x-4))}}}