Question 378096
Use the Pythagorean Theorem from geometry to find the other leg of the right triangle.

(leg)^2 + (given leg)^2 = (hypotenuse)^2


(leg)^2 + (12)^2 = 16^2


(leg)^2 + 144 = 256


(leg)^2 = 256 - 144


(leg)^2 = 112


Take square root of both sides.


sqrt[(leg)^2] = sqrt[112]


leg = sqrt[112]


Let leg = x


Then x = sqrt[112].


Understand?



sinx = sqrt[112]/16


cosx = 12/16


tanx = sqrt[112]/12


cscx = 16/sqrt[112]


secx = 16/12


cotx = 12/sqrt[112]


Done!