Question 41568
a)Find the time to the nearest half-minute, for the population to grow to 7600
{{{B = 1000e^(0.312t)}}}
{{{7600 = 1000e^(0.312t)}}}
{{{7.6 = e^(0.312t)}}}
{{{ln(7.6) = ln(e^(0.312t))}}}
{{{ln(7.6) = (0.312t)log(e,e)}}}
{{{ln(7.6)/0.312 = t}}}
{{{6.5 = t}}}
b) How many bacteria were present initially?
{{{B = 1000e^(0.312t)}}}
{{{B = 1000e^(0.312(0))}}}
{{{B = 1000}}}