Question 378100
{{{f(2) = 2^3 + 7*2 - 22 = 0}}}.  So x = 2 is a zero.  Applying synthetic division the quotient is {{{x^2 + 2x + 11}}}.  The zeros of this are 
{{{x = (-2 +- sqrt( 2^2-4*1*11 ))/2  = (-2 +- sqrt(-40 ))/2 = -1 +- sqrt(10 )i}}}.
{{{f(x) = (x-2)(x +1 - sqrt(10 )i)(x + 1 + sqrt(10 )i)}}}.