Question 378099
x-2y=2


x=2y+2



y^2-x^2=2x+4


y^2-(2y+2)^2=2(2y+2)+4



y^2-(4y^2+8y+4)=4y+4+4



y^2-4y^2-8y-4=4y+8


y^2-4y^2-8y-4-4y-8=0


-3y^2-12y-12=0


y^2+4y+4=0


(y+2)^2=0


y+2=0


y=-2


x=2y+2=2(-2)+2=-4+2=-2


Answers: x=-2, y=-2