Question 377912
let shorter leg be x
longer leg = 3x-6
hypotenuse = 26 cm
...
Pythagoras theorem 
x^2+(3x-6)^2= 26^2
x^2+9x^2-36x+36=26^2
10x^2-36x+36-676=0
10x^2-36x-640=0
10x^2-100x+64x-640=0
10x(x-10)+64(x-10)=0
(10x+64)(x-10)=0
c= 10 which is positive
one leg is 10 cm
the other leg = 3x-6 = 30-6 =24cm
..
m.ananth@hotmail.ca