Question 41578
kx+3y=k-3
12x+ky=k
   solve for k

Taking each equation separately to get:
1st: kx+3y=k-3
     kx-k=-3y-3
     k(x-1)=-3(y-1)
        k = -3(y-1)/(x-1)
2nd: k=12x+ky
    k-ky=12x
    k(1-y)=12x 
    k = 12x/(1-y)

Cheers,
Stan H>