Question 377909
 h*(x)= 7x/x*(x^2-9)
h(x)=7/(x^2-9)
=7/((x+3)(x-3))
x cannot be 3 or -3 because there would be division by zero.
The domain is all real numbers except 3 and -3.
.
{{{graph(500,500,-10,10,-10,10,7/(x^2-9))}}}