Question 377901
let the numbers be x , y , z
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x+y+z=18...........1
x+y =15............2
x= 3z..............3
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x+y =15
plug in (1)
15+z= 18
-15
{{{(highlight(z=3))}}}
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x=3z
{{{(highlight(x= 9))}}}
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x+y+z=18
9+3+y=18
12+y=18
-12
y = 18-12
{{{(highlight(y =6))}}}.
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numbers are 9, 6, 3
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