Question 377702
To find the stationary points you have to get the derivative of y and then equate to zero.  Then y' = {{{5x^4 - 3x^2}}} = {{{x^2(5x^2 - 3)}}} = 0.  Then x = -0.775, 0, 0.775.  At x = -0.775 there is a local max; at x = 0.775 there is a local min; at x = o there is an inflection point (neither a local max nor a local min; concavity changes from  + to -).