Question 377632
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Hi,
Find the center and radius of the circle
The standard equation of a circle with center C(h,k) and radius r is :
{{{(x - h)^2 + (y - k)^2 = r^2}}}
x^2+y^2-6x+2y+6=0
(x-3)^2 + (y+1)^2 -9 -1 + 6 = 0
(x-3)^2 + (y+1)^2 = 4
(x-3)^2 + (y+1)^2 = 2^2
Center is Pt(3,-1) r = 2