Question 377574
{{{y^2=2/3y+5/7}}}
{{{y^2-(2/3)y-5/7=0}}}
Use the discriminant,
{{{D=b^2-4ac}}}
{{{D=(2/3)^2-4(1)(-5/7)}}}
{{{D=4/9+20/7}}}
In this case, {{{D>0}}}.
The solutions are therefore two real solutions.
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{{{graph(300,300,-5,5,-5,5,0,x^2-(2/3)x-5/7)}}}